cos0+cos1°+cos2°+cos3°+............+cos360° =?
的有关信息介绍如下:
首先我们知道:(1) cosα=cos(α+2π) , (2) cosα= -cos(π-α) (π=180°)由(1)可得:cos360°=cos0°cos359°=cos1°……cos179°=cos181°cos180°=cos180°-->cos0+cos1°+cos2°+cos3°+............+cos360° =2(cos0+cos1°+……+cos179°+cos180°)由(2)可得:cos180°= -cos0cos179°= -cos1°……cos89°= -cos91°cos90°= -cos90°-->cos0+cos1°+……+cos179°+cos180°=0cos0+cos1°+cos2°+cos3°+............+cos360° =0

